integral from 0 to 1 of (-y-1/2 e^y)

Lösung

\int_{0}^{1} (- y - \frac{1}{2} e^{y}) d y

- \frac{1}{2} - \frac{e - 1}{2}

Dezimale

- 1.35914 \dots

Schritte zur Lösung

\int_{0}^{1} - y - \frac{1}{2} e^{y} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} y d y - \int_{0}^{1} \frac{1}{2} e^{y} d y

\int_{0}^{1} y d y = \frac{1}{2}

\int_{0}^{1} \frac{1}{2} e^{y} d y = \frac{e - 1}{2}

= - \frac{1}{2} - \frac{e - 1}{2}

\int_{- 1}^{3} 1 + (2 y + 3)^{2} d y

\int_{0}^{b} (a - a \frac{x}{b}) d x

\int_{- 1}^{1} x \frac{3}{4} (1 - x^{2}) d x

\int_{0}^{1} (3 x^{2} - 2 x)^{2} d x

\int_{0}^{t} \frac{1}{1 - x} d x