integral from-1 to 1 of-x^2+9

Lösung

\int_{- 1}^{1} - x^{2} + 9 d x

\frac{52}{3}

Dezimale

17.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} - x^{2} + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} 9 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 9 d x = 18

= - \frac{2}{3} + 18

Vereinfache

- \frac{2}{3} + 18 : \frac{52}{3}

= \frac{52}{3}

\int_{0}^{3} \frac{3 x - 2}{x + 1} d x

\int_{0}^{8} \frac{2 x - 4}{x + 1} d x

\int_{0}^{- 2.5} 100 x d x

\int_{0}^{8} 7 + 3 x d x

\int_{- 6}^{- 3} 2 x^{2} + 16 x + 34 d x