integral from 0 to 1 of (2+x^3)

Lösung

\int_{0}^{1} (2 + x^{3}) d x

\frac{9}{4}

Dezimale

2.25

Schritte zur Lösung

\int_{0}^{1} 2 + x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 d x + \int_{0}^{1} x^{3} d x

\int_{0}^{1} 2 d x = 2

\int_{0}^{1} x^{3} d x = \frac{1}{4}

= 2 + \frac{1}{4}

Vereinfache

2 + \frac{1}{4} : \frac{9}{4}

= \frac{9}{4}

\int_{0}^{5} \frac{1}{x ^{2} - 6 x + 9} d x

\int_{0}^{6} x (6 - x) d x

\int_{1}^{5} k (5 - x) d x

\int_{0}^{2} (x + 1)^{\frac{2}{3}} d x

\int_{2}^{4} - 4 x^{3} ln (x) d x