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人気のある微分積分 >

integral from 0 to pi of asin(x)

解

\int_{0}^{π} a sin (x) d x

解

a \cdot 2

解答ステップ

\int_{0}^{π} a sin (x) d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a \cdot \int_{0}^{π} sin (x) d x

共通積分を使用する:

\int sin (x) d x = - cos (x)

= a [- cos (x)]_{0}^{π}

限度を計算する:

2

= a \cdot 2

人気の例

integral from 4 to 2 of-2

\int_{4}^{2} - 2 d x

integral from 4 to 9 of (2+sqrt(t))/t

\int_{4}^{9} \frac{2 + t}{t} d t

integral from 2 to 7 of 5arccot(x)

\int_{2}^{7} 5 arccot (x) d x

integral from 0 to 3 of 5^xln(5)

\int_{0}^{3} 5^{x} ln (5) d x

integral from 1 to 3 of (x^2-2)/(x+1)

\int_{1}^{3} \frac{x ^{2} - 2}{x + 1} d x