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人気のある微分積分 >

integral from 1 to a of 1/(y^2)

解

\int_{1}^{a} \frac{1}{y ^{2}} d y

解

- \frac{1}{a} + 1

解答ステップ

\int_{1}^{a} \frac{1}{y ^{2}} d y

べき乗則を適用する

= [- \frac{1}{y}]_{1}^{a}

限度を計算する:

- \frac{1}{a} + 1

= - \frac{1}{a} + 1

人気の例

integral from 0 to 4 of |(1-x)|

\int_{0}^{4} ∣ (1 - x) ∣ d x

integral from 0 to 2 of (4-x-y)

\int_{0}^{2} (4 - x - y) d y

integral from 0 to 1 of sin(x)ln(cos(x))

\int_{0}^{1} sin (x) ln (cos (x)) d x

integral from 0 to 1 of (u^2)/(u^2+1)

\int_{0}^{1} \frac{u ^{2}}{u ^{2} + 1} d u

integral from-6 to infinity of 1/(x+8)

\int_{- 6}^{\infty} \frac{1}{x + 8} d x