integral from 2 to 6 of 16-2x

解答

\int_{2}^{6} 16 - 2 x d x

32

求解步骤

\int_{2}^{6} 16 - 2 x d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} 16 d x - \int_{2}^{6} 2 x d x

\int_{2}^{6} 16 d x = 64

\int_{2}^{6} 2 x d x = 32

= 64 - 32

化简

= 32

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