ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 2 to 0 of 2x

解

\int_{2}^{0} 2 x d x

解

- 4

解答ステップ

\int_{2}^{0} 2 x d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{2} 2 x d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int_{0}^{2} x d x

べき乗則を適用する

= - 2 [\frac{x ^{2}}{2}]_{0}^{2}

限度を計算する:

2

= - 2 \cdot 2

簡素化

= - 4

グラフ

人気の例

integral from-1.6 to 0 of pi((6x-x^2))^2

\int_{- 1.6}^{0} π ((6 x - x^{2}))^{2} d x

integral from 0 to x of sec^2(t)

\int_{0}^{x} sec^{2} (t) d t

integral from 0 to 1 of e^xsqrt(1+e^x)

\int_{0}^{1} e^{x} 1 + e^{x} d x

integral from 0 to 1 of x^2sqrt(4x+7)

\int_{0}^{1} x^{2} 4 x + 7 d x

integral from 0 to 2 of 38z^2ln(z)

\int_{0}^{2} 38 z^{2} ln (z) d z