integral from 1 to 4 of-2x+6

解答

\int_{1}^{4} - 2 x + 6 d x

3

求解步骤

\int_{1}^{4} - 2 x + 6 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{4} 2 x d x + \int_{1}^{4} 6 d x

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} 6 d x = 18

= - 15 + 18

化简

= 3

\int_{- 1}^{2} \frac{1}{x ^{2} - 4 x + 13} d x

\int_{1}^{2} - x^{3} + 3 x^{2} - 2 x d x

\int_{1}^{2} π (4 - \frac{1}{2} x)^{2} d x

\int_{0}^{1} x^{3} + x e^{- x} d x

\int_{0}^{\infty} 4 e^{- t} d t