integral from 0 to 6 of (x-1)

Lösung

\int_{0}^{6} (x - 1) d x

12

Schritte zur Lösung

\int_{0}^{6} x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} x d x - \int_{0}^{6} 1 d x

\int_{0}^{6} x d x = 18

\int_{0}^{6} 1 d x = 6

= 18 - 6

Vereinfache

= 12

\int_{1}^{2} \frac{2 x + 5}{x ^{2}} d x

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\int_{0}^{2} 3 x - \frac{3}{2} d x

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\int_{4}^{7} (x^{2} + x + 2) d x