integral from 0 to 4 of (1+2e^{-0.8q})

Lösung

\int_{0}^{4} (1 + 2 e^{- 0.8 q}) d q

6.39809 \dots

Schritte zur Lösung

\int_{0}^{4} 1 + 2 e^{- 0.8 q} d q

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 1 d q + \int_{0}^{4} 2 e^{- 0.8 q} d q

\int_{0}^{4} 1 d q = 4

\int_{0}^{4} 2 e^{- 0.8 q} d q = 2.39809 \dots

= 4 + 2.39809 \dots

Vereinfache

= 6.39809 \dots

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