integral from 0 to pi of 2+cos(x)

Lösung

\int_{0}^{π} 2 + cos (x) d x

2 π

Dezimale

6.28318 \dots

Schritte zur Lösung

\int_{0}^{π} 2 + cos (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 d x + \int_{0}^{π} cos (x) d x

\int_{0}^{π} 2 d x = 2 π

\int_{0}^{π} cos (x) d x = 0

= 2 π + 0

Vereinfache

= 2 π

\int_{0}^{\frac{π}{4}} e^{- x} sin (x) d x

\int_{0}^{3} (x 1 + x) d x

\int_{0}^{r} b \cdot r^{3} + c \cdot r^{2} d r

\int_{0}^{2} \frac{π}{2} r d r

\int_{1}^{3} 2 x - x^{2} d x