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人気のある微分積分 >

integral from 0 to 1 of x^3+(x^4)/2

解

\int_{0}^{1} x^{3} + \frac{x ^{4}}{2} d x

解

\frac{7}{20}

+1

十進法表記

0.35

解答ステップ

\int_{0}^{1} x^{3} + \frac{x ^{4}}{2} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x + \int_{0}^{1} \frac{x ^{4}}{2} d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} \frac{x ^{4}}{2} d x = \frac{1}{10}

= \frac{1}{4} + \frac{1}{10}

簡素化

\frac{1}{4} + \frac{1}{10} : \frac{7}{20}

= \frac{7}{20}

グラフ

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