integral from-1 to 2 of (2-5x+(x^2)/2)

Lösung

\int_{- 1}^{2} (2 - 5 x + \frac{x ^{2}}{2}) d x

0

Schritte zur Lösung

\int_{- 1}^{2} 2 - 5 x + \frac{x ^{2}}{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 d x - \int_{- 1}^{2} 5 x d x + \int_{- 1}^{2} \frac{x ^{2}}{2} d x

\int_{- 1}^{2} 2 d x = 6

\int_{- 1}^{2} 5 x d x = \frac{15}{2}

\int_{- 1}^{2} \frac{x ^{2}}{2} d x = \frac{3}{2}

= 6 - \frac{15}{2} + \frac{3}{2}

Vereinfache

6 - \frac{15}{2} + \frac{3}{2} : 0

= 0

\int_{0}^{3} x^{3} - x^{2} d x

\int_{e}^{2 e} \frac{1}{x ln ^{2} ( x )} d x

\int_{0}^{1} \frac{3}{5} x d x

\int_{1}^{0} x^{3} e^{2 x} d x

\int_{0}^{1} y - y d y