integral from-2 to 5 of x^2+2x+4

Lösung

\int_{- 2}^{5} x^{2} + 2 x + 4 d x

\frac{280}{3}

Dezimale

93.33333 \dots

Schritte zur Lösung

\int_{- 2}^{5} x^{2} + 2 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{5} x^{2} d x + \int_{- 2}^{5} 2 x d x + \int_{- 2}^{5} 4 d x

\int_{- 2}^{5} x^{2} d x = \frac{133}{3}

\int_{- 2}^{5} 2 x d x = 21

\int_{- 2}^{5} 4 d x = 28

= \frac{133}{3} + 21 + 28

Vereinfache

\frac{133}{3} + 21 + 28 : \frac{280}{3}

= \frac{280}{3}

\int_{0}^{\infty} c e^{- 3 x} d x

\int_{0}^{2} 2 x - cos (4 x) d x

\int_{0}^{9} 2 π x (x) d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} \frac{1}{x ^{3}} d x

\int_{1}^{2} ln ((4 x)^{2}) d x