integral from 1 to 2 of 5/(t^6)

Lösung

\int_{1}^{2} \frac{5}{t ^{6}} d t

\frac{31}{32}

Dezimale

0.96875

Schritte zur Lösung

\int_{1}^{2} \frac{5}{t ^{6}} d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{1}^{2} \frac{1}{t ^{6}} d t

Wende die Potenzregel an

= 5 [- \frac{1}{5 t ^{5}}]_{1}^{2}

Berechne die Grenzen:

\frac{31}{160}

= 5 \cdot \frac{31}{160}

Vereinfache

= \frac{31}{32}

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