What is the derivative of 2+ln(x) ?

The derivative of 2+ln(x) is 1/x

What is the first derivative of 2+ln(x) ?

The first derivative of 2+ln(x) is 1/x

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\frac{d}{d x} (2 + ln (x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (2 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

\frac{d}{d x} (ln (1 + x^{4}))

\int_{4}^{\infty} e^{- \frac{y}{2}} d y

\int (sin (5 x) sin (x)) d x

\int \frac{x}{2 ( x + 1 ) 2 x + 1} d x

\frac{d}{d x} (\frac{x ^{3}}{3} - \frac{3}{x ^{5}} + 4 π)

What is the derivative of 2+ln(x) ?
The derivative of 2+ln(x) is 1/x
What is the first derivative of 2+ln(x) ?
The first derivative of 2+ln(x) is 1/x