integral from 0 to 1 of xcosh(2x)

Lösung

\int_{0}^{1} x cosh (2 x) d x

\frac{e ^{4} - 3}{8 e ^{2}} + \frac{1}{4}

Dezimale

1.12288 \dots

Schritte zur Lösung

\int_{0}^{1} x cosh (2 x) d x

Wende die partielle Integration an

= [\frac{1}{2} x sinh (2 x) - \int \frac{1}{2} sinh (2 x) d x]_{0}^{1}

\int \frac{1}{2} sinh (2 x) d x = \frac{1}{4} cosh (2 x)

= [\frac{1}{2} x sinh (2 x) - \frac{1}{4} cosh (2 x)]_{0}^{1}

Berechne die Grenzen:

\frac{e ^{4} - 3}{8 e ^{2}} + \frac{1}{4}

= \frac{e ^{4} - 3}{8 e ^{2}} + \frac{1}{4}

\int_{3}^{6} x - 2 d x

\int_{x^{2}}^{8 - x^{2}} 1 d y

\int_{3}^{9} 7 arctan (x) d x

\int_{2}^{3} x^{3} - 8 d x

\int_{0}^{\infty} e^{- t} t^{7} d t