integral from 1500 to 2500 of k/(x^3)

Lösung

\int_{1500}^{2500} \frac{k}{x ^{3}} d x

\frac{k}{7031250}

Schritte zur Lösung

\int_{1500}^{2500} \frac{k}{x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{1500}^{2500} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= k [- \frac{1}{2 x ^{2}}]_{1500}^{2500}

Berechne die Grenzen:

\frac{1}{7031250}

= k \frac{1}{7031250}

Vereinfache

= \frac{k}{7031250}

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