integral from 1 to 5 of (-x+10)

Lösung

\int_{1}^{5} (- x + 10) d x

28

Schritte zur Lösung

\int_{1}^{5} - x + 10 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{5} x d x + \int_{1}^{5} 10 d x

\int_{1}^{5} x d x = 12

\int_{1}^{5} 10 d x = 40

= - 12 + 40

Vereinfache

= 28

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