integral from-1 to 2 of (x+1)^4

Lösung

\int_{- 1}^{2} (x + 1)^{4} d x

\frac{243}{5}

Dezimale

48.6

Schritte zur Lösung

\int_{- 1}^{2} (x + 1)^{4} d x

Wende U-Substitution an

= \int_{0}^{3} u^{4} d u

Wende die Potenzregel an

= [\frac{u ^{5}}{5}]_{0}^{3}

Berechne die Grenzen:

\frac{243}{5}

= \frac{243}{5}

\int_{1}^{x} (2 - t) d t

\int_{1}^{2} x (1 + x^{2})^{3} d x

\int_{2}^{\infty} \frac{1}{5 x - 1} d x

\int_{- 2}^{5} x^{2} - 2 x - 3 d x

\int_{- 1}^{3} u (1 - 2 u) d u