integral from 1 to 4 of sqrt(3x-2)

Lösung

\int_{1}^{4} 3 x - 2 d x

\frac{20 10 - 2}{9}

Dezimale

6.80506 \dots

Schritte zur Lösung

\int_{1}^{4} 3 x - 2 d x

Wende U-Substitution an

= \int_{1}^{10} \frac{u}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{1}^{10} u d u

Wende die Potenzregel an

= \frac{1}{3} [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{10}

Berechne die Grenzen:

\frac{20 10}{3} - \frac{2}{3}

= \frac{1}{3} (\frac{20 10}{3} - \frac{2}{3})

Vereinfache

= \frac{20 10 - 2}{9}

\int_{5}^{10} \frac{( 5 - x ) ^{4}}{625} d x

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\int_{- 4}^{0} (x + 1) d x

\int_{- \infty}^{- 2} \frac{1}{1 - x} d x