integral from 0 to 1 of (x^{-2}+3e^{3x})

解答

\int_{0}^{1} (x^{- 2} + 3 e^{3 x}) d x

发散

求解步骤

\int_{0}^{1} x^{- 2} + 3 e^{3 x} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{- 2} d x + \int_{0}^{1} 3 e^{3 x} d x

\int_{0}^{1} x^{- 2} d x =

发散

如果表达式有部分发散，则整个表达式发散

= 发散

\int_{- 1}^{0} ∣ 4 w + 3 ∣ d w

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