integral from 0 to 6 of |x^2-4x|

Lösung

\int_{0}^{6} x^{2} - 4 x d x

\frac{64}{3}

Dezimale

21.33333 \dots

Schritte zur Lösung

\int_{0}^{6} x^{2} - 4 x d x

Entferne die Extremwerte

= \int_{0}^{4} - x^{2} + 4 x d x + \int_{4}^{6} x^{2} - 4 x d x

\int_{0}^{4} - x^{2} + 4 x d x = \frac{32}{3}

\int_{4}^{6} x^{2} - 4 x d x = \frac{32}{3}

= \frac{32}{3} + \frac{32}{3}

Vereinfache

\frac{32}{3} + \frac{32}{3} : \frac{64}{3}

= \frac{64}{3}

\int_{0}^{1} \frac{2 x}{x ^{2} + 2} d x

\int_{1}^{4} 3 x - 1 d x

\int_{1}^{3} 12 sin (6 x - 5) d x

\int_{1}^{\infty} \frac{2}{x ^{5}} d x

\int_{0}^{2 π} sin^{2} (\frac{1}{3} θ) d θ