integral from 2 to 5 of 1/((x-2)^n)

Lösung

\int_{2}^{5} \frac{1}{( x - 2 ) ^{n}} d x

\frac{3 ^{- n + 1}}{- n + 1}

Schritte zur Lösung

\int_{2}^{5} \frac{1}{( x - 2 ) ^{n}} d x

Wende U-Substitution an

= \int_{0}^{3} \frac{1}{u ^{n}} d u

Wende die Potenzregel an

= [\frac{u ^{- n + 1}}{- n + 1}]_{0}^{3}

Berechne die Grenzen:

\frac{3 ^{- n + 1}}{- n + 1}

= \frac{3 ^{- n + 1}}{- n + 1}

\int_{1}^{2} (\frac{1}{x} + y) d x

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