integral of tan(4x)sec(4x)

解答

\int tan (4 x) sec (4 x) d x

\frac{1}{4} sec (4 x) + C

求解步骤

\int tan (4 x) sec (4 x) d x

使用换元积分法

= \int \frac{1}{4} d u

常数积分:

\int a d x = a x

= \frac{1}{4} u

u = sec (4 x)

代回

= \frac{1}{4} sec (4 x)

解答补常数

= \frac{1}{4} sec (4 x) + C

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