integral of 1/(x(x+6))

Lösung

\int \frac{1}{x ( x + 6 )} d x

\frac{1}{6} ln ∣ x ∣ - \frac{1}{6} ln ∣ x + 6 ∣ + C

Schritte zur Lösung

\int \frac{1}{x ( x + 6 )} d x

Ermittle den Partialbruch von

\frac{1}{x ( x + 6 )} : \frac{1}{6 x} - \frac{1}{6 ( x + 6 )}

= \int \frac{1}{6 x} - \frac{1}{6 ( x + 6 )} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{6 x} d x - \int \frac{1}{6 ( x + 6 )} d x

\int \frac{1}{6 x} d x = \frac{1}{6} ln ∣ x ∣

\int \frac{1}{6 ( x + 6 )} d x = \frac{1}{6} ln ∣ x + 6 ∣

= \frac{1}{6} ln ∣ x ∣ - \frac{1}{6} ln ∣ x + 6 ∣

Füge eine Konstante zur Lösung hinzu

= \frac{1}{6} ln ∣ x ∣ - \frac{1}{6} ln ∣ x + 6 ∣ + C

\int \frac{x ^{8}}{( 25 - x ^{2} ) ^{\frac{11}{2}}} d x

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