What is the first derivative of 2e^x ?

The first derivative of 2e^x is 2e^x

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derivative of 2e^x

derivative of

2 e^{x}

2 e^{x}

Solution steps

\frac{d}{d x} (2 e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x})

Apply the common derivative:

\frac{d}{d x} (e^{x}) = e^{x}

= 2 e^{x}

\int_{0}^{1} 2 + 2 + x^{2} d x

\int - 40

\frac{d}{d x} (\frac{sin ( 4 x )}{2 + cos ( 4 x )})

\frac{d y}{d x} = \frac{x ^{2} - y ^{2}}{3 x y}

\int 33 + 8 x - x^{2} d x