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Beliebt Rechnen >

integral of ((2x-1)/(x^2-x+8))

Lösung

\int (\frac{2 x - 1}{x ^{2} - x + 8}) d x

Lösung

ln 4 x^{2} - 4 x + 32 + C

Schritte zur Lösung

\int \frac{2 x - 1}{x ^{2} - x + 8} d x

Multipliziere aus

\frac{2 x - 1}{x ^{2} - x + 8} : \frac{2 x}{x ^{2} - x + 8} - \frac{1}{x ^{2} - x + 8}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x}{x ^{2} - x + 8} d x - \int \frac{1}{x ^{2} - x + 8} d x

\int \frac{2 x}{x ^{2} - x + 8} d x = ln 4 x^{2} - 4 x + 32 + \frac{2}{31} arctan (\frac{2 x - 1}{31})

\int \frac{1}{x ^{2} - x + 8} d x = \frac{2}{31} arctan (\frac{2 x - 1}{31})

= ln 4 x^{2} - 4 x + 32 + \frac{2}{31} arctan (\frac{2 x - 1}{31}) - \frac{2}{31} arctan (\frac{2 x - 1}{31})

Addiere gleiche Elemente:

\frac{2}{31} arctan (\frac{2 x - 1}{31}) - \frac{2}{31} arctan (\frac{2 x - 1}{31}) = 0

= ln 4 x^{2} - 4 x + 32

Füge eine Konstante zur Lösung hinzu

= ln 4 x^{2} - 4 x + 32 + C

Graph

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