integral of (p/(2x^2)+pq)

Lösung

\int (\frac{p}{2 x ^{2}} + pq) d x

- \frac{p}{2 x} + pq x + C

Schritte zur Lösung

\int \frac{p}{2 x ^{2}} + pq d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{p}{2 x ^{2}} d x + \int pq d x

\int \frac{p}{2 x ^{2}} d x = - \frac{p}{2 x}

\int pq d x = pq x

= - \frac{p}{2 x} + pq x

Füge eine Konstante zur Lösung hinzu

= - \frac{p}{2 x} + pq x + C

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