What is the integral of 4x^2cos(x) ?

The integral of 4x^2cos(x) is 4(x^2sin(x)-2(-xcos(x)+sin(x)))+C

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integral of 4x^2cos(x)

\int 4 x^{2} cos (x) d x

4 (x^{2} sin (x) - 2 (- x cos (x) + sin (x))) + C

Solution steps

\int 4 x^{2} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x^{2} cos (x) d x

Apply Integration By Parts

= 4 (x^{2} sin (x) - \int 2 x sin (x) d x)

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= 4 (x^{2} sin (x) - 2 (- x cos (x) + sin (x)))

Add a constant to the solution

= 4 (x^{2} sin (x) - 2 (- x cos (x) + sin (x))) + C

\int 6 x^{2} - 4 x + 2 d x

\int \frac{x ^{2} + x}{x ^{2} - 1} d x

\int \frac{x ^{2} + x + 1}{( 2 x + 1 ) ( x ^{2} + 1 )} d x

\int \frac{1}{x ^{\frac{3}{4}} - x ^{\frac{1}{4}}} d x

\int (18 x^{5} - 12 x^{3} + 4 x) d x

What is the integral of 4x^2cos(x) ?
The integral of 4x^2cos(x) is 4(x^2sin(x)-2(-xcos(x)+sin(x)))+C