What is the integral of x^3sin(x^4+2) ?

The integral of x^3sin(x^4+2) is -1/4 cos(x^4+2)+C

integral of x^3sin(x^4+2)

\int x^{3} sin (x^{4} + 2) d x

- \frac{1}{4} cos (x^{4} + 2) + C

Solution steps

\int x^{3} sin (x^{4} + 2) d x

Apply u-substitution

= \int \frac{sin ( u )}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{4} (- cos (u))

Substitute back

u = x^{4} + 2

= \frac{1}{4} (- cos (x^{4} + 2))

Simplify

= - \frac{1}{4} cos (x^{4} + 2)

Add a constant to the solution

= - \frac{1}{4} cos (x^{4} + 2) + C

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What is the integral of x^3sin(x^4+2) ?
The integral of x^3sin(x^4+2) is -1/4 cos(x^4+2)+C