What is the integral of 5sec^2(5x) ?

The integral of 5sec^2(5x) is tan(5x)+C

integral of 5sec^2(5x)

\int 5 sec^{2} (5 x) d x

tan (5 x) + C

Solution steps

\int 5 sec^{2} (5 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int sec^{2} (5 x) d x

Apply u-substitution

= 5 \cdot \int sec^{2} (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{5} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= 5 \cdot \frac{1}{5} tan (u)

Substitute back

u = 5 x

= 5 \cdot \frac{1}{5} tan (5 x)

Simplify

5 \cdot \frac{1}{5} tan (5 x) : tan (5 x)

= tan (5 x)

Add a constant to the solution

= tan (5 x) + C

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