What is the integral of (2(x^5-x^3+4))/(x^5) ?

The integral of (2(x^5-x^3+4))/(x^5) is 2(x+1/x-1/(x^4))+C

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integral of (2(x^5-x^3+4))/(x^5)

\int \frac{2 ( x ^{5} - x ^{3} + 4 )}{x ^{5}} d x

2 (x + \frac{1}{x} - \frac{1}{x ^{4}}) + C

Solution steps

\int \frac{2 ( x ^{5} - x ^{3} + 4 )}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{x ^{5} - x ^{3} + 4}{x ^{5}} d x

Expand

\frac{x ^{5} - x ^{3} + 4}{x ^{5}} : 1 - \frac{1}{x ^{2}} + \frac{4}{x ^{5}}

= 2 \cdot \int 1 - \frac{1}{x ^{2}} + \frac{4}{x ^{5}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int 1 d x - \int \frac{1}{x ^{2}} d x + \int \frac{4}{x ^{5}} d x)

\int 1 d x = x

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

\int \frac{4}{x ^{5}} d x = - \frac{1}{x ^{4}}

= 2 (x - (- \frac{1}{x}) - \frac{1}{x ^{4}})

Simplify

= 2 (x + \frac{1}{x} - \frac{1}{x ^{4}})

Add a constant to the solution

= 2 (x + \frac{1}{x} - \frac{1}{x ^{4}}) + C

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What is the integral of (2(x^5-x^3+4))/(x^5) ?
The integral of (2(x^5-x^3+4))/(x^5) is 2(x+1/x-1/(x^4))+C