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Frequently Asked Questions (FAQ)
What is the solution for y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=-1 ?
- The solution for y^{''}+12y^'+36y=0,y(1)=0,y^'(1)=-1 is y=e^{6-6t}-e^{6-6t}t