What is the solution for f^'(x)=x^3+8x-5x+6 ?

The solution for f^'(x)=x^3+8x-5x+6 is f(x)=(x^4)/4+(3x^2)/2+6x+c_{1}

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f^'(x)=x^3+8x-5x+6

f^{^{'}} (x) = x^{3} + 8 x - 5 x + 6

f (x) = \frac{x ^{4}}{4} + \frac{3 x ^{2}}{2} + 6 x + c_{1}

Solution steps

f^{'} (x) = x^{3} + 8 x - 5 x + 6

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x^{3} + 8 x - 5 x + 6 d x

\int x^{3} + 8 x - 5 x + 6 d x = \frac{x ^{4}}{4} + \frac{3 x ^{2}}{2} + 6 x + c_{1}

f (x) = \frac{x ^{4}}{4} + \frac{3 x ^{2}}{2} + 6 x + c_{1}

What is the solution for f^'(x)=x^3+8x-5x+6 ?
The solution for f^'(x)=x^3+8x-5x+6 is f(x)=(x^4)/4+(3x^2)/2+6x+c_{1}