(d^3-d^2+2)y=0

Lösung

(d^{3} - d^{2} + 2) y = 0

y = c_{1} e^{- x} + e^{x} (c_{2} cos (x) + c_{3} sin (x))

Schritte zur Lösung

(d^{3} - d^{2} + 2) y = 0

Solve linear ODE:

y = c_{1} e^{- x} + e^{x} (c_{2} cos (x) + c_{3} sin (x))

y = c_{1} e^{- x} + e^{x} (c_{2} cos (x) + c_{3} sin (x))

(d^{5} + 2 d^{3} + d) y = 0

(d^{3} - 3 d^{2} + 3 d - 1) y = 0

y^{^{''}} - 4 y = 0, y^{^{'}} (0) = 0

y^{^{'''}} + 5 y^{^{''}} + 17 y^{^{'}} + 13 y = 0

(d^{3} + d) \cdot y = 0