What is the solution for y^{''}+2y^'-3y=e^2x ?

The solution for y^{''}+2y^'-3y=e^2x is y=c_{1}e^x+c_{2}e^{-3x}-(e^2x)/3-(2e^2)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y^'-3y=e^2x

y^{^{''}} + 2 y^{^{'}} - 3 y = e^{2} x

y = c_{1} e^{x} + c_{2} e^{- 3 x} - \frac{e ^{2} x}{3} - \frac{2 e ^{2}}{9}

Solution steps

y^{''} (x) + 2 y^{'} (x) - 3 y = e^{2} x

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 3 x} - \frac{e ^{2} x}{3} - \frac{2 e ^{2}}{9}

y = c_{1} e^{x} + c_{2} e^{- 3 x} - \frac{e ^{2} x}{3} - \frac{2 e ^{2}}{9}

y^{^{''}} + y = 2 t cos (t) cos^{2} (t)

y^{^{''}} - 2 y^{^{'}} - 8 y = 5 e^{2} x

(d^{2} + 1) y = e^{- x} + cos (x) + x^{3}

y^{^{''}} + y^{^{'}} = x + sin (2 x)

(2 d^{2} - d - 3) y = 25 e^{- x}

What is the solution for y^{''}+2y^'-3y=e^2x ?
The solution for y^{''}+2y^'-3y=e^2x is y=c_{1}e^x+c_{2}e^{-3x}-(e^2x)/3-(2e^2)/9