What is the integral of 1/((s+a)) ?

The integral of 1/((s+a)) is ln|s+a|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/((s+a))

integral

\frac{1}{( s + a )}

ln ∣ s + a ∣ + C

Solution steps

\int \frac{1}{s + a} d s

Apply u-substitution

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = s + a

= ln ∣ s + a ∣

Add a constant to the solution

= ln ∣ s + a ∣ + C

in t e g r a l - 3 v + 5

in t e g r a l \frac{1}{( 10 - 2 e ^{2} x )}

in t e g r a l \frac{1}{( sin ( x ) cot ^{2} ( x ) )}

in t e g r a l \frac{1}{( ( x - 3 ) ( x + 7 ) )}

in t e g r a l - 5 cos (\frac{x}{2})