integral ((x+8))/(sqrt(x+7))

Lösung

integral

\frac{( x + 8 )}{x + 7}

2 (\frac{1}{3} (x + 7)^{\frac{3}{2}} + x + 7) + C

Schritte zur Lösung

\int \frac{x + 8}{x + 7} d x

Wende U-Substitution an

= \int 2 (u^{2} + 1) d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int u^{2} + 1 d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u^{2} d u + \int 1 d u)

\int u^{2} d u = \frac{u ^{3}}{3}

\int 1 d u = u

= 2 (\frac{u ^{3}}{3} + u)

Setze in

u = x + 7

ein

= 2 (\frac{( x + 7 ) ^{3}}{3} + x + 7)

Vereinfache

2 (\frac{( x + 7 ) ^{3}}{3} + x + 7) : 2 (\frac{1}{3} (x + 7)^{\frac{3}{2}} + x + 7)

= 2 (\frac{1}{3} (x + 7)^{\frac{3}{2}} + x + 7)

Füge eine Konstante zur Lösung hinzu

= 2 (\frac{1}{3} (x + 7)^{\frac{3}{2}} + x + 7) + C

in t e g r a l \frac{1}{x ^{2} + y ^{2}}

in t e g r a l \frac{( 1 + x ^{2} )}{( 1 - x ^{3} )}

in t e g r a l \frac{1}{1 + x ^{4}}

in t e g r a l 1 - sin^{2} (x)

in t e g r a l 1 - ∣ x ∣