What is the integral of 1/(7[ 1/x ]) ?

The integral of 1/(7[ 1/x ]) is (x^2)/(14)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(7[ 1/x ])

integral

\frac{1}{7 [ \frac{1}{x} ]}

\frac{x ^{2}}{14} + C

Solution steps

\int \frac{1}{7 [ \frac{1}{x} ]} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int \frac{1}{[ \frac{1}{x} ]} d x

Simplify

= \frac{1}{7} \cdot \int x d x

Apply the Power Rule

= \frac{1}{7} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{7} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{14}

= \frac{x ^{2}}{14}

Add a constant to the solution

= \frac{x ^{2}}{14} + C

in t e g r a l \frac{( 3 t + 4 )}{( 2 t + 3 )}

in t e g r a l \frac{1}{( x ^{2} + x - 2 )}

in t e g r a l (4 x + 9)^{\frac{1}{2}}

in t e g r a l (2 x + 8)^{3}

in t e g r a l \frac{1}{1 + x ^{3}}

What is the integral of 1/(7[ 1/x ]) ?
The integral of 1/(7[ 1/x ]) is (x^2)/(14)+C