What is the derivative of log_{10}(2/x) ?

The derivative of log_{10}(2/x) is -1/(ln(10)x)

What is the first derivative of log_{10}(2/x) ?

The first derivative of log_{10}(2/x) is -1/(ln(10)x)

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derivative of

lo g_{10} (\frac{2}{x})

- \frac{1}{ln ( 10 ) x}

Solution steps

\frac{d}{d x} (lo g_{10} (\frac{2}{x}))

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

= \frac{d}{d x} (\frac{ln ( \frac{2}{x} )}{ln ( 10 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 10 )} \frac{d}{d x} (ln (\frac{2}{x}))

Apply the chain rule:

\frac{1}{\frac{2}{x}} \frac{d}{d x} (\frac{2}{x})

= \frac{1}{\frac{2}{x}} \frac{d}{d x} (\frac{2}{x})

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= \frac{1}{ln ( 10 )} \cdot \frac{1}{\frac{2}{x}} (- \frac{2}{x ^{2}})

Simplify

\frac{1}{ln ( 10 )} \cdot \frac{1}{\frac{2}{x}} (- \frac{2}{x ^{2}}) : - \frac{1}{ln ( 10 ) x}

= - \frac{1}{ln ( 10 ) x}

d er i v a t i v e \frac{( 3 x ^{2} - 1 ) ^{2}}{( x + 1 ) ^{3}}

d er i v a t i v e 1 4^{x} + 16

d er i v a t i v e \frac{2 x - 3}{x}

d er i v a t i v e y = x + 2 sin (x) + 2

d er i v a t i v e x^{\frac{1}{2}} + x^{2}

What is the derivative of log_{10}(2/x) ?
The derivative of log_{10}(2/x) is -1/(ln(10)x)
What is the first derivative of log_{10}(2/x) ?
The first derivative of log_{10}(2/x) is -1/(ln(10)x)