What is the derivative of y/((x-y)2) ?

The derivative of y/((x-y)2) is x/(2(x-y)^2)

What is the first derivative of y/((x-y)2) ?

The first derivative of y/((x-y)2) is x/(2(x-y)^2)

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derivative of

\frac{y}{( x - y ) 2}

\frac{x}{2 ( x - y ) ^{2}}

Solution steps

\frac{d}{d y} (\frac{y}{( x - y ) \cdot 2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d y} (\frac{y}{x - y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d y}{d y} ( x - y ) - \frac{d}{d y} ( x - y ) y}{( x - y ) ^{2}}

\frac{d y}{d y} = 1

\frac{d}{d y} (x - y) = - 1

= \frac{1}{2} \cdot \frac{1 \cdot ( x - y ) - ( - 1 ) y}{( x - y ) ^{2}}

Simplify

\frac{1}{2} \cdot \frac{1 \cdot ( x - y ) - ( - 1 ) y}{( x - y ) ^{2}} : \frac{x}{2 ( x - y ) ^{2}}

= \frac{x}{2 ( x - y ) ^{2}}

\frac{d}{d x} (3 ∣ sin (x) x ∣ - 4 ∣ cos (x) ∣)

d er i v a t i v e \frac{a}{( a - t ) ^{2}}

d er i v a t i v e cos (6 x + 2)

d er i v a t i v e \frac{1}{p}

\frac{d}{d y} (\frac{y}{2 x + 1})

What is the derivative of y/((x-y)2) ?
The derivative of y/((x-y)2) is x/(2(x-y)^2)
What is the first derivative of y/((x-y)2) ?
The first derivative of y/((x-y)2) is x/(2(x-y)^2)