What is the first derivative of 2y+1 ?

The first derivative of 2y+1 is 2

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derivative of 2y+1

derivative of

2 y + 1

2

Solution steps

\frac{d}{d y} (2 y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (2 y) + \frac{d}{d y} (1)

\frac{d}{d y} (2 y) = 2

\frac{d}{d y} (1) = 0

= 2 + 0

Simplify

= 2

d er i v a t i v e \frac{e ^{x}}{( 1 - e ^{x} )}

d er i v a t i v e y = \frac{- x ^{2}}{2}

\frac{d}{d a} (\frac{a}{b - 3})

d er i v a t i v e 100 + 5 q^{2}

\frac{d}{d j} (12 i - 19 j)