What is the first derivative of 3q^2 ?

The first derivative of 3q^2 is 6q

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derivative of 3q^2

derivative of

3 q^{2}

6 q

Solution steps

\frac{d}{d q} (3 q^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d q} (q^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 q^{2 - 1}

Simplify

= 6 q

\frac{d}{d x} ((x^{2} + y^{2} + z^{2})^{3})

2 x + y

\frac{d}{dd} (d + 7)

y = x + 2 x sin (x)

y = tan (- x + 1)