What is the derivative of f(x)=x^3+1 ?

The derivative of f(x)=x^3+1 is 3x^2

What is the first derivative of f(x)=x^3+1 ?

The first derivative of f(x)=x^3+1 is 3x^2

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derivative of

f (x) = x^{3} + 1

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\frac{8 x}{3}

y = x^{3} + 4 x^{2} + 5 x + 7

x + 11

\frac{3}{x ^{4}}

\frac{d}{d t} (5 t + 16 t^{2})

What is the derivative of f(x)=x^3+1 ?
The derivative of f(x)=x^3+1 is 3x^2
What is the first derivative of f(x)=x^3+1 ?
The first derivative of f(x)=x^3+1 is 3x^2