What is the derivative of 1+sin^2(x) ?

The derivative of 1+sin^2(x) is sin(2x)

What is the first derivative of 1+sin^2(x) ?

The first derivative of 1+sin^2(x) is sin(2x)

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derivative of

1 + sin^{2} (x)

sin (2 x)

Solution steps

\frac{d}{d x} (1 + sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sin^{2} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= 0 + sin (2 x)

Simplify

= sin (2 x)

d er i v a t i v e 2 e^{3} x

d er i v a t i v e y = 2 x^{5}

d er i v a t i v e \frac{1}{arctan ( 2 x + 1 )}

d er i v a t i v e ((sin (x))^{x})^{2}

d er i v a t i v e \frac{1}{2 x}

What is the derivative of 1+sin^2(x) ?
The derivative of 1+sin^2(x) is sin(2x)
What is the first derivative of 1+sin^2(x) ?
The first derivative of 1+sin^2(x) is sin(2x)