What is the first derivative of 2x^2+2 ?

The first derivative of 2x^2+2 is 4x

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derivative of 2x^2+2

derivative of

2 x^{2} + 2

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2) = 0

= 4 x + 0

Simplify

= 4 x

d er i v a t i v e sin^{- 2} (x)

d er i v a t i v e \frac{( x + 1 )}{2}

d er i v a t i v e y = \frac{2 x ^{2} - x + 4}{x}

d er i v a t i v e x (x^{2} - 1)^{\frac{1}{2}}

\frac{d}{d q} ((1 + csc (q)) cos (q))