What is the limit as x approaches 0+of x/(x^2+1) ?

The limit as x approaches 0+of x/(x^2+1) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 0+of x/(x^2+1)

x \to 0 + lim (\frac{x}{x ^{2} + 1})

0

Solution steps

x \to 0 + lim (\frac{x}{x ^{2} + 1})

Plug in the value

x = 0

= \frac{0}{0 ^{2} + 1}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

x \to \infty lim (\frac{1}{6} ln (tanh (\frac{3 x}{2})))

x \to 1 lim (\frac{2 x - 2}{3 26 + x - 3})

x \to \frac{π}{2} + lim (tan (π - x))

x \to 3 lim (2 x - 2)

x \to \infty lim (\frac{2 x}{2 ^{x} ln ( 2 )})

What is the limit as x approaches 0+of x/(x^2+1) ?
The limit as x approaches 0+of x/(x^2+1) is 0