What is the limit as h approaches 0 of (2/(8+h)-8)/h ?

The limit as h approaches 0 of (2/(8+h)-8)/h is diverges

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limit as h approaches 0 of (2/(8+h)-8)/h

h \to 0 lim (\frac{\frac{2}{8 + h} - 8}{h})

diverges

Solution steps

h \to 0 lim (\frac{\frac{2}{8 + h} - 8}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{\frac{2}{8 + h} - 8}{h}) = - \infty

h \to 0 - lim (\frac{\frac{2}{8 + h} - 8}{h}) = \infty

= diverges

x \to - 2 lim (- x^{2} + 3 x + 4)

x \to 0 lim (a^{m x})

h \to 0 lim (\frac{1 - cos ( h )}{h})

x \to - 3 lim (4 x^{2} - 3 x + 1)

x \to - 2 lim (\frac{x + 1}{x ^{2} - 1})

What is the limit as h approaches 0 of (2/(8+h)-8)/h ?
The limit as h approaches 0 of (2/(8+h)-8)/h is diverges