integral from 0 to 4 of |x-2|

解答

\int_{0}^{4} ∣ x - 2 ∣ d x

4

求解步骤

\int_{0}^{4} ∣ x - 2 ∣ d x

拿掉绝对值

= \int_{0}^{2} - x + 2 d x + \int_{2}^{4} x - 2 d x

\int_{0}^{2} - x + 2 d x = 2

\int_{2}^{4} x - 2 d x = 2

= 2 + 2

化简

= 4

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